傅里叶级数展开matlab实现

傅里叶级数展开matlab 实现 给个例子说明下:将函数 y=x*(x-pi)*(x-2*pi),在(0,2*pi)的范围内傅里叶级数展 开 syms x fx=x*(x-pi)*(x-2*pi);

傅里叶级数展开matlab实现 傅里叶级数展开实现给个例子说明下将函数 matlab: 在的范围内傅里叶级数展开 y=x*(x-pi)*(x-2*pi),(0,2*pi) symsxfx=x*(x-pi)*(x-2*pi); 前项展开 [an,bn,f]=fseries(fx,x,12,0,2*pi)%12latex(f)% 将转换成代码 flatexan=[0,0,0,0,0,0,0,0,0,0,0, 0,0]bn=[-12,3/2,-4/9,3/16,-12/125,1/18, -12/343,3/128,-4/243,3/250,-12/1331,1/144]f= 12*sin(x)+3/2*sin(2*x)+4/9*sin(3*x)+3/16*sin(4*x)+12 /125*sin(5*x)+1/18*sin(6 *x)+12/343*sin(7*x)+3/128*sin(8*x)+4/243*sin(9*x)+3 /250*sin(10*x)+12/1331*sin(11*x)+1/144*sin(12*x) ans=12\,\sin\left(x\right)+3/2\,\sin\left(2\,x \right)+4/9\,\sin\left(3\,x\right)+3/16\,\sin\left( 4\,x\right)+{\frac{12}{125}}\,\sin\left(5\,x\right) +1/18\,\sin\left(6\,x\right)+{\frac{12}{343}}\,\sin \left(7\,x\right)+{\frac{3}{128}}\,\sin\left(8\,x\right) +{\frac{4}{243}}\,\sin\left(9\,x\right)+{\frac {3}{250}}\,\sin\left(10\,x\right)+{\frac {12}{1331}}\,\sin\left(11\,x\right)+{\frac {1}{144}}\,\sin\left(12\,x\right)function 傅里叶级数展开为 [an,bn,f]=fseries(fx,x,n,a,b)%%%an 余弦项系数为正弦项系数为 fourier%bnfourier%f